Optimal. Leaf size=196 \[ -\frac{2 a^2 (5 A-C) \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}+\frac{8 a^2 (A+C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}-\frac{4 a^2 (A-C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}+\frac{8 A \sin (c+d x) \sqrt{\sec (c+d x)} \left (a^2 \cos (c+d x)+a^2\right )}{3 d}+\frac{2 A \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
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Rubi [A] time = 0.543133, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.229, Rules used = {4221, 3044, 2975, 2968, 3023, 2748, 2641, 2639} \[ -\frac{2 a^2 (5 A-C) \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}+\frac{8 a^2 (A+C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}-\frac{4 a^2 (A-C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}+\frac{8 A \sin (c+d x) \sqrt{\sec (c+d x)} \left (a^2 \cos (c+d x)+a^2\right )}{3 d}+\frac{2 A \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 4221
Rule 3044
Rule 2975
Rule 2968
Rule 3023
Rule 2748
Rule 2641
Rule 2639
Rubi steps
\begin{align*} \int (a+a \cos (c+d x))^2 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac{5}{2}}(c+d x) \, dx &=\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{(a+a \cos (c+d x))^2 \left (A+C \cos ^2(c+d x)\right )}{\cos ^{\frac{5}{2}}(c+d x)} \, dx\\ &=\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{\left (2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{(a+a \cos (c+d x))^2 \left (2 a A-\frac{3}{2} a (A-C) \cos (c+d x)\right )}{\cos ^{\frac{3}{2}}(c+d x)} \, dx}{3 a}\\ &=\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{\left (4 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{(a+a \cos (c+d x)) \left (\frac{3}{4} a^2 (3 A+C)-\frac{3}{4} a^2 (5 A-C) \cos (c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx}{3 a}\\ &=\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{\left (4 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\frac{3}{4} a^3 (3 A+C)+\left (-\frac{3}{4} a^3 (5 A-C)+\frac{3}{4} a^3 (3 A+C)\right ) \cos (c+d x)-\frac{3}{4} a^3 (5 A-C) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{3 a}\\ &=-\frac{2 a^2 (5 A-C) \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{\left (8 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\frac{3}{2} a^3 (A+C)-\frac{9}{4} a^3 (A-C) \cos (c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{9 a}\\ &=-\frac{2 a^2 (5 A-C) \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}-\left (2 a^2 (A-C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx+\frac{1}{3} \left (4 a^2 (A+C) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=-\frac{4 a^2 (A-C) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{d}+\frac{8 a^2 (A+C) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{3 d}-\frac{2 a^2 (5 A-C) \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}\\ \end{align*}
Mathematica [C] time = 1.67731, size = 191, normalized size = 0.97 \[ \frac{a^2 e^{-i d x} \sec ^{\frac{3}{2}}(c+d x) (\cos (d x)+i \sin (d x)) \left (4 i (A-C) \left (1+e^{2 i (c+d x)}\right )^{3/2} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};-e^{2 i (c+d x)}\right )+16 (A+C) \cos ^{\frac{3}{2}}(c+d x) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )+4 A \sin (c+d x)+12 A \sin (2 (c+d x))-12 i A \cos (2 (c+d x))-12 i A+C \sin (c+d x)+C \sin (3 (c+d x))+12 i C \cos (2 (c+d x))+12 i C\right )}{6 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 2.576, size = 651, normalized size = 3.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (a \cos \left (d x + c\right ) + a\right )}^{2} \sec \left (d x + c\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (C a^{2} \cos \left (d x + c\right )^{4} + 2 \, C a^{2} \cos \left (d x + c\right )^{3} +{\left (A + C\right )} a^{2} \cos \left (d x + c\right )^{2} + 2 \, A a^{2} \cos \left (d x + c\right ) + A a^{2}\right )} \sec \left (d x + c\right )^{\frac{5}{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (a \cos \left (d x + c\right ) + a\right )}^{2} \sec \left (d x + c\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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